y = f'(x0)(x - x0) + f(x0)
f'(x) = 3x² - 6x
f'(-2) = 12 + 12 = 24
f(-2) = -8 - 12 = -20
y = 24(x+2) - 20 = 24x + 28
ответ: y = 24x + 28
y = f'(x0)(x - x0) + f(x0)
f'(x) = 3x² - 6x
f'(-2) = 12 + 12 = 24
f(-2) = -8 - 12 = -20
y = 24(x+2) - 20 = 24x + 28
ответ: y = 24x + 28