В урне имеется 4 шара с номерами 1, 2, 3, 4. Вынули 2 шара. Случайная величина – сумма номеров вынутых шаров. Для случайной величины: а) построить ряд распределения; б) найти математическое ожидание и дисперсию; в) построить функцию распределения вероятностей.
1) 5/38 * 1 1/3 = (5*4)/ (38*3) =(5*2)/(19*3)= 10/57
2) 10/57-10/57 =0
3) 2 3/4 : 4 8/9= 11/4 : 44/9= 11/4* 9/44= (1*9)/(4*4)= 9/16
4) 9/16 * 2 2/3 = (9*8)/(16*3)= (3*1)/ (2*1) = 3/2 = 1 1/2
5) 5/6 + 1 1/2 = 5/6 + 1 3/6= 2 2/6 = 2 1/3
6) 2 1/3 - 1 2/3 = 7/3 - 5/3= 2/3
Выражение:
5/6 + 2 3/4 : 4 8/9 * 2 2/3 - 1 2/3 + (5/38 * 1 1/3 - 10/57)=
= 5/6 + (11*9*8)/(4*44*3) - 1 2/3 + ( (5*4)/ (38*3) - 10/57)=
= 5/6 + (1*3*1)/ (1*2*1) - 1 2/3 + ( (5*2)/(19*3) - 10/57)=
= 5/6 + 3/2 - 1 2/3 +0 = 5/6+9/6 - 10/6 =4/6= 2/3
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