1)(3x-5)(2x-1)=0 2) (3x-5)(2x-1)=5 3) (3x-5)(2x-1)=2x-1 - вопрос №13521023521533521215419569 от ayer1 14.10.2020 23:00

Question

Алгебра: 1)(3x-5)(2x-1)=0 2) (3x-5)(2x-1)=5 3) (3x-5)(2x-1)=2x-1 -решите уравнения

ayer1 · Answer

1) (3x - 5)(2x - 1) = 03x - 5 = 03x = 5x = 5/32x - 1 = 02x = 1x = 1/22) ( 3x - 5)(2x - 1) = 56x^2 - 13x + 5 - 5 = 06x^2 - 13x = 0x(6x - 13) = 0x = 06x - 13 = 06x = 13x = 13/6x = 2целых 1/63) (3x - 5)(2x - 1) = 2x - 16x^2 - 13x + 5 - 2x + 1 = 06x^2 - 15x + 6 = 0D = b^2 - 4ac = 225 - 144 = 81 = 9^2x1 = ( 15 + 9)/ 12 = 2x2 = ( 15 - 9) / 12 = 0,5...