1) cos2x=1/2 2) sinx/3=√3/2 3) tgx/2=√3 4) ctg3x=√3/3 - вопрос №12122332323433354306720731450904 от Sevinch123 19.11.2020 21:52

Question

Алгебра: 1) cos2x=1/2 2) sinx/3=√3/2 3) tgx/2=√3 4) ctg3x=√3/3 5) 4sinx+3=0 6) 7cosx-2=0 7) tg3x+10=0 8) 12ctg2x=5

Sevinch123 · Answer

cos2x=1/2 2x = ± + 2n, n ∈ Z x = ±  +     = (-1)⁻n n, n ∈ Z x = (-1)⁻n n, n ∈ Z   n, n ∈ Z x = n, n ∈ Z ...