1) log6 (- 3x + 12) =2* 2)log5(-4x+5)= -1* - вопрос №1631222545116463508 от gilev2004stepaxa 22.01.2021 18:45

Question

Алгебра: 1) log6 (- 3x + 12) =2* 2)log5(-4x+5)= -1*

gilev2004stepaxa · Answer

1) log₆ ( - 3x + 12 ) = 2

log₆ ( - 3x + 12 ) = 2, x < 4

- 3x + 12 = 6²

- 3x + 12 = 36

- 3x = 36 - 12

- 3x = 24

x = - 8

ответ: x = - 8

2) log₆ ( -4x + 5 )= - 1

log₆ ( -4x + 5 )= - 1, x < $\frac{5}{4}$

-4x + 5 = 6 ⁻¹

-4x + 5 = $\frac{1}{6}$

-4x = $\frac{1}{6}$ - 5

-4x = - $\frac{29}{6}$

x = $\frac{29}{24}$

x = 1 $\frac{5}{24}$

ответ: 1 $\frac{5}{24}$