1)x^2+x/4-3-7x/20=0,3 2) 1/2x^2-3x-9+3/x^2-x-6=x/2x^2+7x+6 - вопрос №12437200321223932622765986182 от мивое 20.07.2020 18:17

Question

Алгебра: 1)x^2+x/4-3-7x/20=0,3 2) 1/2x^2-3x-9+3/x^2-x-6=x/2x^2+7x+6

мивое · Answer

1) 0,3x+8=2 0.3x=2-8 0.3x=-6 x=-6/0.3 x = -20

2) 4-x=1+4x -x-4x=1-4 -5x=-3 x=-3/(-5) x = 0.6

3) 7-2(x+3)=9-6x -2x+6x=9-7+6 4x=8 x=8/4 x = 2

4) 4(x-0.5)-2(x+0.3)=-2.6 4x-2x = -2.6+2+0.6 2x = 0 x=0/2 x = 0

5) 0.4x-6= -12 0.4x = -12+6 0.4x = -6 x = -6/0.4 x = -15

6) x+6=5+4x x-4x=5-6 -3x = -1 x = -1/(-3) x = 1/3

7) 13-3(x+1) = 4-5x -3x +5x = 4-13+3 2x = -6 x = -6/2 x = -3

8) 0.2(3x-5)-0.3(x-1) = -0.7 0.6x - 0.3x = -0.7+1-0.3 0.3x = 0 x = 0/0.3 x = 0