15.9. 1) z(2 2 – 5) + 5(2 2 – 5) = 0; 2) 3(4-2) – 72(2 – 4) = 0;
3) 2(0,52 + 5) – 6(5 + 0,5г);
4) 2(8 - 2) +2 – 8 = 0.
Паногон пены (15 10—15.11):

Question

Алгебра: 15.9. 1) z(2 2 – 5) + 5(2 2 – 5) = 0; 2) 3(4-2) – 72(2 – 4) = 0; 3) 2(0,52 + 5) – 6(5 + 0,5г); 4) 2(8 - 2) +2 – 8 = 0. Паногон пены (15 10—15.11):

rajbowa1 · Answer

8y - (3y + 5) = 3 (2y - 1)
8y - 3y - 5 = 6y - 3
5y - 5 = 6y - 3
5y - 6y = -3 + 5
-y = 2
y = 2

5y² - 2y = 0
y(5y - 2) = 0
y₁ = 0
5y - 2 = 0
5y = 2
y= 2/5
y₂ = 0.4

(a-b)² + 3a - 3b = (a-b)(a-b) + 3(a-b) = (a-b)(a-b+3)

Система:
{2(x+5) =9 - 3(4+y)
{21 +6x+ 4y = 4(2x+5)

{2х + 10 = 9 - 12 -3у
{ 21 + 6x +4y = 8x + 20

{2x + 3y = - 3 - 10
{6x + 4y - 8x = 20 - 21

{ 2x + 3y = -13
{-2x + 4y = - 1
метод сложения:
2х + 3у -2х + 4у = -13 - 1
7у = -14
у = -14/7
у = -2
2х + 3*(-2) = -13
2х -6 = -13
2х = -13 +6
2х=-7
х= - 7/2
х = -3,5
ответ: (-3,5; -2)