новым годом!
x^2+4x = 5
x^2+4x-5 = 0
x^2+5x-x-5 = 0
x(x+5)-(x+5) = 0
(x+5)*(x-1) = 0
x+5 = 0 x(1) = -5
⇒
x-1 = 0 x(2) = 1
ответ: х(1) = -5, х(2) = 1
х²+4х-5=0
D=16+20=36
x1=-4+6/2=1
x2=-4-6/2=-5
Корни:1,-5
новым годом!
x^2+4x = 5
x^2+4x-5 = 0
x^2+5x-x-5 = 0
x(x+5)-(x+5) = 0
(x+5)*(x-1) = 0
x+5 = 0 x(1) = -5
⇒
x-1 = 0 x(2) = 1
ответ: х(1) = -5, х(2) = 1
х²+4х-5=0
D=16+20=36
x1=-4+6/2=1
x2=-4-6/2=-5
Корни:1,-5