f(x) = x³ - 10x² + x + 5
1) f'(x) = (x³ - 10x² + x + 5)' = 3x² - 20x + 1
2) f''(x) = (3x² - 20x + 1)' = 6x - 20
f''(x) = 6x - 20
f(x) = x³ - 10x² + x + 5
1) f'(x) = (x³ - 10x² + x + 5)' = 3x² - 20x + 1
2) f''(x) = (3x² - 20x + 1)' = 6x - 20
f''(x) = 6x - 20