(х2+х-5) (х2+х+1) =-9
замена x2+x-2=t
(t - 3)(t + 3) = -9
t2 - 9 = -9
t2 = 0
t = 0
x2 + x - 2 =0
D=b^2-4ac = 1 +8 = 9
x12=(-1 +- 3)/2 = -2 1
ответ -2 и 1
(х2+х-5) (х2+х+1) =-9
замена x2+x-2=t
(t - 3)(t + 3) = -9
t2 - 9 = -9
t2 = 0
t = 0
x2 + x - 2 =0
D=b^2-4ac = 1 +8 = 9
x12=(-1 +- 3)/2 = -2 1
ответ -2 и 1