1/5-у - 6 = 1-6у / у |*y(5-y) ОДЗ: у≠0 5-y≠01у-6у(5-у)=(1-6у)(5-у) y≠5
1у-30у+6у^2=5-у-30у+6у^2
1y-30y+6^2-5+y+30y-6y^2=0
1y+y-5=02y=5y=2:5y=2.5
1 1-6y
- 6 =
5-y y
1-30+6y/5-y=1-6y/y
6y^2-29y=5y-30y^2
36y^2-34y=0
2y*(18y-17)=0
y=0 или 18y-17=0
y=17/18 ответ:0, 17/18.
1/5-у - 6 = 1-6у / у |*y(5-y) ОДЗ: у≠0 5-y≠0
1у-6у(5-у)=(1-6у)(5-у) y≠5
1у-30у+6у^2=5-у-30у+6у^2
1y-30y+6^2-5+y+30y-6y^2=0
1y+y-5=0
2y=5
y=2:5
y=2.5
1 1-6y
- 6 =
5-y y
1-30+6y/5-y=1-6y/y
6y^2-29y=5y-30y^2
36y^2-34y=0
2y*(18y-17)=0
y=0 или 18y-17=0
y=17/18 ответ:0, 17/18.