Решите уравнение 1)(3a+1)^2-10=(a+3)(a-3) 2)10m+(2-m)^2=63-(3-m)^2 - вопрос №13121033210226332343224982639 от dstepin17 19.08.2022 02:55

Question

Алгебра: Решите уравнение 1)(3a+1)^2-10=(a+3)(a-3) 2)10m+(2-m)^2=63-(3-m)^2 3)(x+4)(x+3)+(x-2)(x+2)=2(3x+4)

dstepin17 · Answer

1) 9a² + 6a + 1 - 10 = a² - 99a² - a² + 6a - 9 +9 = 08a² + 6a = 02a(4a + 3) = 02a = 0a = 04a + 3 =04a = -3a = - 3/410m + 4 - 4m + m² = 63 - (9 - 6m + m²)m² + 6m + 4 = 63 - 9 + 6m - m²m² + m² + 6m - 6m = 54 - 42m² = 50m² = 25m = 5m = - 5x² +7x + 12 + x² - 4 = 6x + 82x²  + 7x - 6x + 8 -8 = 02x² + x = 0x( 2x + 1) = 0x = 02x + 1 = 02x = - 1x = - 0,5...