x2+2x=3
x2+2x-3=0
x2+3x-x-3=0
x*(x+3)-(x+3)=0
(x*3)*(x-1)=0
x+3=0 x-1=0
x=-3 x=1
x1=-3, x2=1
x^2 + 2x = 3
x^2 +2x -3 = 0
D = 4 - 4×(-3) = 4 + 12 = 16>0
x1 = -2+4 / 2 = 1
x2 = -2-4 / 2 = -3
ответ: 1; -3.
x2+2x=3
x2+2x-3=0
x2+3x-x-3=0
x*(x+3)-(x+3)=0
(x*3)*(x-1)=0
x+3=0 x-1=0
x=-3 x=1
x1=-3, x2=1
x^2 + 2x = 3
x^2 +2x -3 = 0
D = 4 - 4×(-3) = 4 + 12 = 16>0
x1 = -2+4 / 2 = 1
x2 = -2-4 / 2 = -3
ответ: 1; -3.