1-х²=0 х₁=1 х₂= -1
∫¹₋₁ (1-х²)dx = x- (x³/3)|¹₋₁ =(1- 1/3) - (-1 -(-1/3)) =2/3 -(-2/3) = 4/3 = 1. 1/3 ед²
1-х²=0 х₁=1 х₂= -1
∫¹₋₁ (1-х²)dx = x- (x³/3)|¹₋₁ =(1- 1/3) - (-1 -(-1/3)) =2/3 -(-2/3) = 4/3 = 1. 1/3 ед²