Яке значення матиме логічний вираз a>8 , якщо a=5? a = 10

ответ:"objName": "Stage",

"lists": [{

  "listName": "dummy",

  "contents": [],

  "isPersistent": false,

  "target": "Stage",

  "x": 5,

  "y": 5,

  "width": 102,

  "height": 202,

  "visible": true

 }],

"sounds": [{

  "soundName": "pop",

  "soundID": 0,

  "md5": "83a9787d4cb6f3b7632b4ddfebf74367.wav",

  "sampleCount": 258,

  "rate": 11025,

  "format": ""

 }],

"costumes": [{

  "costumeName": "backdrop1",

  "baseLayerID": 3,

  "baseLayerMD5": "790f7842ea100f71b34e5b9a5bfbcaa1.svg",

  "rotationCenterX": 240,

  "rotationCenterY": 180

 }],

"currentCostumeIndex": 0,

"penLayerMD5": "279467d0d49e152706ed66539b577c00.png",

"tempoBPM": 60,

"children": [{

  "objName": "Scratch Cat",

  "scripts": [[53,

    47.8,

    [["procDef", "Fill %s with %s , %n times", ["list", "a", "n"], ["", "", 1], true],

     ["doRepeat", ["getParam", "n"], [["append:toList:", ["getParam", "a"], "dummy",

  "sounds": [{

    "soundName": "pop",

    "soundID": 0,

    "md5": "83a9787d4cb6f3b7632b4ddfebf74367.wav",

    "sampleCount": 258,

    "rate": 11025,

    "format": ""

   }],

  "costumes": [{

    "costumeName": "costume1",

    "baseLayerID": 1,

    "baseLayerMD5": "f9a1c175dbe2e5dee472858dd30d16bb.svg",

    "rotationCenterX": 47,

    "rotationCenterY": 55

   },

   {

    "costumeName": "costume2",

    "baseLayerID": 2,

    "baseLayerMD5": "6e8bd9ae68fdb02b7e1e3df656a75635.svg",

    "rotationCenterX": 47,

    "rotationCenterY": 55

   }],

  "currentCostumeIndex": 0,

  "scratchX": 0,

  "scratchY": 0,

  "scale": 1,

  "direction": 90,

  "rotationStyle": "normal",

  "isDraggable": false,

  "indexInLibrary": 1,

  "visible": true,

  "spriteInfo": {

Объяснение:

A[i] := i + 1;

   PrintLn(a);

   Println();

   for i := 1 to 10 do

   begin

       A[i] := A[i - 1];

       PrintLn(a);

   end;

   Println();

   Println(2);

   for i := 0 to 10 do

       A[i] := i + 1;

   PrintLn(a);

   Println();

   for i := 10 downto 0 do

   begin

       A[i] := A[10 - i];

       PrintLn(a);

   end;

end.

Тут вывод трасировок последних циклов

1

[1,2,3,4,5,6,7,8,9,10,11]

[1,1,3,4,5,6,7,8,9,10,11]

[1,1,1,4,5,6,7,8,9,10,11]

[1,1,1,1,5,6,7,8,9,10,11]

[1,1,1,1,1,6,7,8,9,10,11]

[1,1,1,1,1,1,7,8,9,10,11]

[1,1,1,1,1,1,1,8,9,10,11]

[1,1,1,1,1,1,1,1,9,10,11]

[1,1,1,1,1,1,1,1,1,10,11]

[1,1,1,1,1,1,1,1,1,1,11]

[1,1,1,1,1,1,1,1,1,1,1]

2

[1,2,3,4,5,6,7,8,9,10,11]

[1,2,3,4,5,6,7,8,9,10,1]

[1,2,3,4,5,6,7,8,9,2,1]

[1,2,3,4,5,6,7,8,3,2,1]

[1,2,3,4,5,6,7,4,3,2,1]

[1,2,3,4,5,6,5,4,3,2,1]

[1,2,3,4,5,6,5,4,3,2,1]

[1,2,3,4,5,6,5,4,3,2,1]

[1,2,3,4,5,6,5,4,3,2,1]

[1,2,3,4,5,6,5,4,3,2,1]

[1,2,3,4,5,6,5,4,3,2,1]

[1,2,3,4,5,6,5,4,3,2,1]

Подробнее - на -

Объяснение: