m(HCl)=109.5*0.15=16,425 g
n(HCl)=0.45 mole
CH3CH2NH2 + HCl = [CH3CH2NH3]Cl
n(CH3CH2NH2)=0.45 mole
V=10.08 литров
m(HCl)=109.5*0.15=16,425 g
n(HCl)=0.45 mole
CH3CH2NH2 + HCl = [CH3CH2NH3]Cl
n(CH3CH2NH2)=0.45 mole
V=10.08 литров