m(р-ну) = 219 g
W(HCl) = 20%
V(H2) - ?
m(HCl) = 0.2 * 219 = 43.8 g
n(HCl) = 43.8 / 36.5 = 1.2 mol
1.2 mol x mol
Zn + 2HCl = ZnCl2 + H2
2 mol 1 mol
2:1.2 = 1:x
2x = 1.2
x = 0.6
V(H2) = 0.6 * 22.4 = 13.44 l
m(р-ну) = 219 g
W(HCl) = 20%
V(H2) - ?
m(HCl) = 0.2 * 219 = 43.8 g
n(HCl) = 43.8 / 36.5 = 1.2 mol
1.2 mol x mol
Zn + 2HCl = ZnCl2 + H2
2 mol 1 mol
2:1.2 = 1:x
2x = 1.2
x = 0.6
V(H2) = 0.6 * 22.4 = 13.44 l