дано
m(K) = 3.9 g
m(O2) = 0.8 g
KxOy-?
n(K) = m(K) / M(K) = 3.9 / 39 = 0.1 mol
n(O) = m(O2) / M(O) = 0.8 / 16 = 0.05 mol
n(K) : n(O) = 0.1 : 0.05 = 2:1
K2O
ответ K2O
дано
m(K) = 3.9 g
m(O2) = 0.8 g
KxOy-?
n(K) = m(K) / M(K) = 3.9 / 39 = 0.1 mol
n(O) = m(O2) / M(O) = 0.8 / 16 = 0.05 mol
n(K) : n(O) = 0.1 : 0.05 = 2:1
K2O
ответ K2O