дано
m(ppa CH3COOH) = 300 g
W(CH3COOH) = 6 %
+m2(CH3COOH) = 6g
w(Na2CO3) = 20%
W1(CH3COOH)-?
m ppa (Na2CO3)-?
m(CH3COOH) = 300 * 6% / 100% = 18 g
m1(ppa CH3COOH) =m(ppa CH3COOH)+m2(CH3COOH) = 300 +6 = 306 g
m1(CH3COOH) = m(CH3COOH) + m2(CH3COOH) = 18 + 6 = 24 g
W1(CH3COOH) = m1(CH3COOH) / m1(ppa CH3COOH) * 100%
W1(CH3COOH) = 24 / 306 * 100% = 7.8 %
CH3COOH+Na2CO3-->CH3COONa+H2O+CO2
M(CH3COOH) = 60 g/mol
n(CH3COOH) = m1(ppa CH3COOH) / M(CH3COOH) = 306 / 60 = 5.1 mol
n(CH3COOH) = n(Na2CO3) = 5.1 mol
M(Na2CO3) = 106 g/mol
m(Na2CO3) = n*M = 5.1 * 106 = 540.6 g
m(ppa Na2CO3) = m(Na2CO3) * 100% / w(Na2CO3) = 540.6 * 100% / 20%
m(ppa Na2CO3) = 2703 g
ответ 7.8% , 2703 г
Объяснение:
дано
m(ppa CH3COOH) = 300 g
W(CH3COOH) = 6 %
+m2(CH3COOH) = 6g
w(Na2CO3) = 20%
W1(CH3COOH)-?
m ppa (Na2CO3)-?
m(CH3COOH) = 300 * 6% / 100% = 18 g
m1(ppa CH3COOH) =m(ppa CH3COOH)+m2(CH3COOH) = 300 +6 = 306 g
m1(CH3COOH) = m(CH3COOH) + m2(CH3COOH) = 18 + 6 = 24 g
W1(CH3COOH) = m1(CH3COOH) / m1(ppa CH3COOH) * 100%
W1(CH3COOH) = 24 / 306 * 100% = 7.8 %
CH3COOH+Na2CO3-->CH3COONa+H2O+CO2
M(CH3COOH) = 60 g/mol
n(CH3COOH) = m1(ppa CH3COOH) / M(CH3COOH) = 306 / 60 = 5.1 mol
n(CH3COOH) = n(Na2CO3) = 5.1 mol
M(Na2CO3) = 106 g/mol
m(Na2CO3) = n*M = 5.1 * 106 = 540.6 g
m(ppa Na2CO3) = m(Na2CO3) * 100% / w(Na2CO3) = 540.6 * 100% / 20%
m(ppa Na2CO3) = 2703 g
ответ 7.8% , 2703 г
Объяснение: