1) 4(х+3)-2(3-х)-х-4= 2) 5(х+2)-3(4-+5)х-2= 3) 3(х+5)-5(4-х)-х-3= - вопрос №1432342523452335543453215257393841 от MrAmoral 08.11.2022 00:35

Question

Математика: 1) 4(х+3)-2(3-х)-х-4= 2) 5(х+2)-3(4-+5)х-2= 3) 3(х+5)-5(4-х)-х-3= 4) 5(х+3)-2(1-+5)х-2= 5) 3(х+-+3)х-3= 6) 5(х+2)-5(2-х)-х-1= 7) 2(х+1)-2(3-+2)х-5= 8) х+1-(3-х)-х-1= 9) 4(х+1)-4(4-+4)х-3= 10 5(х+5)-5(3-х)-х-1= !

MrAmoral · Answer

1) 4(х+3)-2(3-х)-х-4=4х+12-6+2х-х-4=5х+2
2) 5(х+2)-3(4-х)-((3+5)х-2=5х+10-12+3х-3х-15-2=5х-19
3) 3(х+5)-5(4-х)-х-3=3х+15-20+5х-х-3=7х-8
4) 5(х+3)-2(1-х)-(2+5)х-2=5х+15-2+2х-2х-5х-2=11
5) 3(х+4)-(1-х)-(1+3)х-3=3х+12-1+х-х-3х-3=8
6) 5(х+2)-5(2-х)-х-1=5х+10-10+5х-х-1=9х-1
7) 2(х+1)-2(3-х)-(2+2)х-5=2х+2-6+2х-2х-2х-5=-9
8) х+1-(3-х)-х-1=х+1-3+х-х-1=х-3
9) 4(х+1)-4(4-х)-(4+4)х-3=4х+4-16+4х-4х-4х-3=-15
10 5(х+5)-5(3-х)-х-1=5х+25-15+5х-х-1=9х+9