1) x^(lg^2 x-3lgx+1) 1000. 2) 5^logx49-7^logx5-2 =0 - вопрос №12311000254975202488058 от efremchina99 01.12.2021 14:57

Question

Математика: 1) x^(lg^2 x-3lgx+1) 1000. 2) 5^logx49-7^logx5-2 =0

efremchina99 · Answer

X^(lg^2 x-3lgx+1) 1000lgX^(lg^2 x-3lgx+1) lg1000(lg^2 x-3lgx+1)lgx 3lg^3 x-3lg^2x+lgx-3 0lg^2x(lgx-3)+(lgx-3) 0(lgx-3)(lg^2x+1) 0lg^2x+1 0  всегдаlgx-3 0lgx 3x 10002) 5^logx49-7^logx5-2 =049^logx5-7^logx5-2 =07^2logx5-7^logx5-2 =07^logx5=t, t 0t^2-t-2 =0(t+1)(t-2) =0, t 0t =2 7^logx5 =2logx5 =log7(2)x^log7(2) =5x =5^log2(7)...

1) x^(lg^2 x-3lgx+1)> 1000. 2) 5^logx49-7^logx5-2> =0