y=x³-5x²+7x-5 x₀=1
f(x₀)=1³-5×1²+7×1-5=-2
f'(x)=(x³)'-(5x²)'+(7x)'-(5)'=3x²-5×2x+7-0=3x²-10x+7
f'(x₀)=3×1²-10×1+7=0
y=f(x₀)+f'(x₀)(x-x₀)=-3+0×(x-1)=-3
y=x³-5x²+7x-5 x₀=1
f(x₀)=1³-5×1²+7×1-5=-2
f'(x)=(x³)'-(5x²)'+(7x)'-(5)'=3x²-5×2x+7-0=3x²-10x+7
f'(x₀)=3×1²-10×1+7=0
y=f(x₀)+f'(x₀)(x-x₀)=-3+0×(x-1)=-3