sin(5x/3+Π/4)=-√3/2;
5x/3+Π/4=(-1)^(k+1)*Π/3+Πk;
5x/3=(-1)^(k+1*Π/3-Π/4+Πk;
x=(-1)^(k+1)*Π/5-3Π/20+3Πk/5, kєz
P.S Вроде всё правильно
sin(5x/3+Π/4)=-√3/2;
5x/3+Π/4=(-1)^(k+1)*Π/3+Πk;
5x/3=(-1)^(k+1*Π/3-Π/4+Πk;
x=(-1)^(k+1)*Π/5-3Π/20+3Πk/5, kєz
P.S Вроде всё правильно