cos^2(3x)-(1-cos^2(3x))-cos3x=0
2*cos^2(3x)-cos(3x) -1=0
cos(3x)=t
2t^2-t-1=0
t=1
t=-0.5
1)cos3x=1
3x=2πn
x=(2πn)/3 (n∈Ζ)
2) cos3x=-0.5
3x=2π/3+2πk ==> x=2π/9+2πk/3 (k∈Ζ).
3x=4π/3+2πl ==> x=4π/3+2πl/3 (l∈Ζ)
cos^2(3x)-(1-cos^2(3x))-cos3x=0
2*cos^2(3x)-cos(3x) -1=0
cos(3x)=t
2t^2-t-1=0
t=1
t=-0.5
1)cos3x=1
3x=2πn
x=(2πn)/3 (n∈Ζ)
2) cos3x=-0.5
3x=2π/3+2πk ==> x=2π/9+2πk/3 (k∈Ζ).
3x=4π/3+2πl ==> x=4π/3+2πl/3 (l∈Ζ)