1)108: 90=42: 5х 2)(7х-3)/4 = (5-2х)/6 3)5/2х = - вопрос №1108904252734526352345264539281017 от banilchik26 28.01.2020 20:47

Question

Математика: 1)108: 90=42: 5х 2)(7х-3)/4 = (5-2х)/6 3)5/2х = 3/(4-х) 5)2/(6-х)= 4/(5х+3)

banilchik26 · Answer

1. 108:90=42:5х1.2=x*1.2=x*=x=xx=2.(7х-3)/4 = (5-2х)/66(7x-3)=4(5-2x)42x-18=20-8x42x+8x=20+1850x=38x=3. 5/2х = 3/(4-х)x=, x45x=5x*(4-x)=65x*(4-x)-6=020x--6=0-+20x-6=05x2-20x+6=0x=x=x=x=x=  x=x=  x=, x4 x_{1} = x_{2} =5. 2/(6-х)= 4/(5х+3), x...